Answer:
Liming reagent in the given reaction is oxygen.
Step-by-step explanation:
Mass of octane = 12.85 g
Mass of oxygen = 7.46 g
Molar mass of octane = 114.23 g/mol
Molar mass of oxygen = 32




According to the reaction, 2 moles of octane requires 25 moles of O2
so, 0.1125 moles of octane requires
of oxygen.
but only 0.2331 mol of oxygen is present.
Hence, oxygen is the limiting reagent