Question

If a disk drive has 8 surfaces and there are 1024 tracks per surface with 256 sectors per track and 512 bytes/sector. What is the capacity of the drive?

Answer 1

Capacity of the drive equals 1073741824 bytes.

Step-by-step explanation:

Since it is given that there are 8 surfaces with 1024 tracks per surface thus the number of tracks in 8 surfaces equals
`8* 1024=8192`

Now since it is given that there are 256 sectors per track thus the number of sectors in 8192 tracks equals
`256* 8192=2097152`

Now since it is given that there are 512 bytes per sector thus the number of bytes in 2097152 sectors are
`512* 2097152=1073741824`

Thus the number of bytes in the memory equals 1073741824 bytes.