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A transformer consists of 290 primary windings and 816 secondary windings. Part a: If the potential difference across the primary coil is 23.0 V , what is the voltage across the secondary coil?

Part b: If the potential difference across the primary coil is 23.0 V , what is the current in the secondary coil if it is connected across a 100 Ω resistor? Express your answer in amperes to three significant figures.

User FVod
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1 Answer

1 vote

Answer:

(A) 64.7172 VOLT (B) 6.471 A

Step-by-step explanation:

We have given number of turns in primary that is
N_1=290

And number of turns in secondary that is
N_2=816

Primary voltage
V_1=23 volt

(a) We have to find the secondary voltage

For transformer we know that
(V_1)/(V_2)=(N_1)/(N_2)


(23)/(V_2)=(290)/(816)


V_2=64.7172volt

(b) It is given that a resistance of 100 ohm is connected across secondary so current in secondary
i=(V)/(R)=(64.7172)/(100)=6.471 A

User Dsghi
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8.6k points