Question

A transformer consists of 290 primary windings and 816 secondary windings. Part a: If the potential difference across the primary coil is 23.0 V , what is the voltage across the secondary coil?

Part b: If the potential difference across the primary coil is 23.0 V , what is the current in the secondary coil if it is connected across a 100 Ω resistor? Express your answer in amperes to three significant figures.

Answer 1

(A) 64.7172 VOLT (B) 6.471 A

Step-by-step explanation:

We have given number of turns in primary that is
`N_1=290`

And number of turns in secondary that is
`N_2=816`

Primary voltage
`V_1=23 volt`

(a) We have to find the secondary voltage

For transformer we know that
`(V_1)/(V_2)=(N_1)/(N_2)`

`(23)/(V_2)=(290)/(816)`

`V_2=64.7172volt`

(b) It is given that a resistance of 100 ohm is connected across secondary so current in secondary
`i=(V)/(R)=(64.7172)/(100)=6.471 A`