Question

IN JAVA, Given a positive int n, return true if it contains a 1 digit. Note: use % to get the rightmost digit, and / to discard the rightmost digit.

hasOne(10) â true
hasOne(22) â false
hasOne(220) â false

Answer 1

Here is code in java.

import java.util.*;

class Solution

{

public static void main (String[] args) throws java.lang.Exception

{

try{

int n;

//scanner class object to read input

Scanner scnr=new Scanner(System.in);

System.out.print("please enter the number:");

// read the input from user

n=scnr.nextInt();

// call the function with argument n

System.out.println(hasOne(n));

}catch(Exception ex){

return;}

}

// method to find "1" in the input number

public static Boolean hasOne(int num)

{

int r;

boolean flag=false;

r=num%10;

while(num>0)

{

//if remainder is 1 then flag will be true

if(r==1)

{

flag=true;

break;

}

// if the remainder is not '1' then it discard the digit

num=num/10;

r=num%10;

}

// returning the value

return flag;

}

}

Step-by-step explanation:

Create a scanner class object "scnr" to read input.Call the function hasOne()

with parameter "n".In the hasOne(),find the remainder and check if it is equal to 1 or not.if it is equal to 1 then set the flag "true" otherwise discard that digit

as "num=num/10".Repeat this until "num>0".This function will return a boolean value base on the presence of "1" in the number.

Output:

please enter the number:10

true

please enter the number:22

false