Question

What is the grating separation (d) that corresponds to a source of wavelength 530.5 nm that produces a line at 44.2°? Calculate this value in nm using m=1.

Answer 1

761 nm

Step-by-step explanation:

We have given the wavelength of source
`\lambda =530.5nm=530.5* 10^(-9)m`

Angle
`\Theta =44.2^(\circ)`

In question it is said that use m= 1

We have to find grating separation

According to law of diffraction

`dsin\Theta =m\lambda`

`dsin44.2 =1* 530.5* 10^(-9)`

`d=761nm`