Question

A reaction of 2.5kg of fissionable material takes place. Assuming a 0.10% mass defect, how much energy is released?

Answer 1

Energy released =
`2.25* 10^(14)\;J`

Step-by-step explanation:

Amount of fissionable material = 2.5 kg

Mass defect = 0.10 % of fissionable material

Mass defect
`=2.5* (0.1)/(100) = 0.0025\; kg`

`E = mc^(2)`

Where,

m = Mass defect in Kg

C = Speed of light m/s2

`C = 3* 10^(8)\;m/s^2`

Now substitute the values in the above equation

`E = 0.0025* (3* 10^(8))^2 = 2.25* 10^(14)\;J`