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Write down the DE of this damped harmonic oscillator.

User Gduh
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1 Answer

5 votes

Answer:


(d^(2)x )/(d^(2)t )+(k)/(m)x+(b)/(m) (dx)/(dt)=0

Step-by-step explanation:

The spring mass equation for the damped oscillation will be,


F=-kx-bv

Here, -bv is the damping term used in this b is damping constant, k is spring constant, x is elongation in the spring, F is the force.


ma=-kx-bv\\m(d^(2)x )/(d^(2)t )=-kx-b(dx)/(dt)\\  m(d^(2)x )/(d^(2)t )+kx+b(dx)/(dt)=0\\(d^(2)x )/(d^(2)t )+(k)/(m)x+(b)/(m) (dx)/(dt)=0

Therefore the differential equation for the damped harmonic oscillator is,


(d^(2)x )/(d^(2)t )+(k)/(m)x+(b)/(m) (dx)/(dt)=0

User Anatoliy Kim
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