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A 68 g sample of copper is at 20â¦C. If 1918 J of energy are added to the copper, what is its final temperature? Assume the specific heat of copper is 387 J/kg ·⦠C. Answer in units of â¦C.

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Answer:

Final temperature of the sample is 92.88 degrees Celsius.

Step-by-step explanation:

It is given that,

Mass of the sample of copper, m = 68 g = 0.068 kg

Initial temperature,
T_1=20^(\circ)C

Energy added to the copper, Q = 1918 J

Specific heat of the copper,
c=387\ J/kg^(\circ)C

We need to find the final temperature of the copper sample. The heat added is given by :


Q=mc\Delta T


Q=mc(T_2-T_1), T₂ is the final temperature


T_2=(Q)/(mc)+T_1


T_2=(1918)/(0.068* 387)+20


T_2=92.88^(\circ) C

So, the final temperature of the copper sample is 92.88 degrees Celsius. Hence, this is the required solution.

User Esteban Gatjens
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