Question

Submit What is the solubility of Cd3(POA) 2 in water? (Ksp of Cd3(PO4)2 is 2.5 x 10-33) | 1 2 3 +/- . 0 x100

Answer 1

Answer: The solubility of
`Cd_3(PO_4)_2` in water is
`1.18* 10^(-7)mol/L`

Step-by-step explanation:

The balanced equilibrium reaction for the ionization of cadmium phosphate follows:

`Cd_3(PO_4)_2\rightleftharpoons 3Cd^(2+)+2PO_4^(3-)`

3s 2s

The expression for solubility constant for this reaction will be:

`K_(sp)=[Cd^(2+)]^3[PO_4^(3-)]^2`

We are given:

`K_(sp)=2.5* 10^(-33)`

Putting values in above equation, we get:

`2.5* 10^(-33)=(3s)^3* (2s)^2\\\\2.5* 10^(-33)=108s^5\\\\s=1.18* 10^(-7)mol/L`

Hence, the solubility of
`Cd_3(PO_4)_2` in water is
`1.18* 10^(-7)mol/L`