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A black hole emits a jet with a power of 1044 W. If the black hole has a rotational period of 0.1 ms, what is the energy emitted by the jet during one rotation of the black hole?

User Janovak
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Answer:

Energy Emitted,
E_(J) = 0.1044 J

Given:

Power of the jet emitted by black hole,
P_(J) = 1044 W

Rotational period of black hole,
\Delta T = 0.1 ms = 0.1* 10^(-3)

Solution:

Energy emitted during one rotation of the black hole is given by:


P_(J) = (Energy emitted, E_(J))/(\Delta T)

Therefore,


E_(J) = P_(J)* \Delta T

Now, putting the given values in the above formula:


E_(J) = 1044* 0.1* 10^(-3) = 0.1044 J

User Yodalr
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