Question

A black hole emits a jet with a power of 1044 W. If the black hole has a rotational period of 0.1 ms, what is the energy emitted by the jet during one rotation of the black hole?

Answer 1

Energy Emitted,
`E_(J) = 0.1044 J`

Given:

Power of the jet emitted by black hole,
`P_(J) = 1044 W`

Rotational period of black hole,
`\Delta T = 0.1 ms = 0.1* 10^(-3)`

Solution:

Energy emitted during one rotation of the black hole is given by:

`P_(J) = (Energy emitted, E_(J))/(\Delta T)`

Therefore,

`E_(J) = P_(J)* \Delta T`

Now, putting the given values in the above formula:

`E_(J) = 1044* 0.1* 10^(-3) = 0.1044 J`