Question

Calculate the solubility at 25 °C of Ni(OH), in pure water and in a 0.0130 M NaOH solution. You'll find K.data in the ALEKS Data tab. Round both of your answers to 2 significant digits. 20 solubility in pure water: solubility in 0.0130 M NaOH solution: 602 xs ?

Answer 1

a) in pure water:

⇒ S (25°C) Ni(OH)2 = 2.0 E-5 M

b) in 0.013 M NaOH:

⇒ S = 9.467 E-11 M

Step-by-step explanation:

a) Ni(OH)2 ↔ Ni2+ + 2OH-

S S 2S

⇒ Ksp = [ Ni2+ ] * [ OH- ]² = 1.6 E-14.....Ksp value comes from the literature

⇒ Ksp = S * 2S² = 1.6 E-14

⇒ 2S³ = 1.6 E-14

⇒ S = ∛( 1.6 E-14 / 2 )

⇒ S = 2.0 E-5 M

b) NaOH ↔ Na+ + OH-

0.0130 M 0.013 0.013

Ni(OH)2 ↔ Ni2+ + 2OH-

S S 2S + 0.0130

⇒ Ksp = [ Ni2+ ] * [ OH- ]²

⇒ Ksp = S * (2S + 0.0130 )² = 1.6 E-14

Due to the small value of the Ksp it can be assumed that "s" is a very small number, so "2s" can be neglected when added to 0.0130.

⇒ 1.6 E-14 = S * ( 0.0130 )²

⇒ S = 9.467 E-11 M