Question

If a disk drive has 8 surfaces and there are 1024 tracks per surface with 256 sectors per track and 512 bytes/sector. What is the capacity of the drive?

Answer 1

The capacity of the drive in Gigabytes equals 1.0737 Gbs

Step-by-step explanation:

Given there are 1024 tracks per surface.

Number of surfaces = 8

Hence number of tracks in 8 surfaces equals
`1024* 8=8192` tracks

Now it is given that there are 256 sectors per track thus the number of sectors in 8192 tracks equals
`8192* 256=2097152` sectors

Now it is given that there are 512 bytes per sector thus the number of bytes in 2097152 equals
`2097152* 512=1073741824` bytes

Converting to gigabytes the capacity of the drive in gigabytes equals 1.0737Gbs