Question

Write a balanced equation for the reaction of propanoic acid with each of the following:

a. KOH

b. H2O

c. NaOH

Answer 1

Step-by-step explanation:

A balanced equation is the one in which there are equal number of moles of both reactant and products.

Reaction of propanoic acid with the given species is as follows.

(a)
`CH_(3)CH_(2)COOH + KOH \rightarrow CH_(3)CH_(2)COO^(-)K^(+) + H_(2)O`

So, when propanoic acid reacts with potassium hydroxide then there will be formation of potassium salt of the acid along with formation of water.

(b) When propanoic acid is dissolved in water then being a strong acid it ionizes completely as follows.

`CH_(3)CH_(2)COOH + H_(2)O \rightarrow CH_(3)CH_(2)COO^(-) + H_(3)O^(+)`

(c) When propanoic acid reacts with sodium hydroxide then there will be formation of sodium salt of the acid along with formation of water.

The reaction equation will be as follows.

`CH_(3)CH_(2)COOH + NaOH \rightarrow CH_(3)CH_(2)COO^(-)Na^(+) + H_(2)O`