Question

14. Write an expression for the output voltage of an ac source that has an amplitude of 12 V and a frequency of 200 Hz

Answer 1

`v = 12sin400\pi t`

Given:

Voltage,
`v_(m) = 12 V`

frequency, f = 200 Hz

Solution:

The expression for output voltage of an AC source is given by:

`v = v_(m)sin\omega t`

where

`\omega = 2\pi f`

Therefore,

`v = v_(m)sin2\pi f t`

Now, using the given values in the output voltage expression for an ac source:

`v = 12sin2\pi * 200`

Thus the expression so formed is:

`v = 12sin400\pi t`