Question

Iron (III) oxide reacts with carbon monoxide to produce iron metal and carbon dioxide. What mass of iron is produced from the reduction of 10.0 g of iron (III) oxide.

Answer 1

7 grams of iron is produced from the reduction of 10.0 g of iron (III) oxide.

Step-by-step explanation:

`Fe_2O_3+3CO\rightarrow 3CO_2+2Fe`

Moles of iron (III) oxide :

`(10.0g)/(160 g/mol)=0.0625 mol`

According to reaction, 1 mol of iron(III) oxide gives 2 moles of iron metal.

Then 0.0625 moles of iron(III) oxide will give:

`(2)/(1)* 0.0625 mol=0.125 mol` of iron metal.

Mass of 0.125 moles of iron metal.

`0.125 mol* 56 g/mol=7 g`

7 grams of iron is produced from the reduction of 10.0 g of iron (III) oxide.