Question

For a ∆x of 0.1mm, what is ∆px, the uncertainty in the transverse momentum of a photon passing through a slit (where uncertainty in x comes from slit width, ∆x=slit width?

Answer 1

`0.53* 10^(-30)kgms^(-1)`

Step-by-step explanation:

Uncertainty principle say that the position and momentum can not be measured simultaneously except one relation which is described below,

`\Delta x\Delta p=(h)/(4\pi )`

Given that the uncertainty in x is 0.1 mm.

Therefore,

`\Delta p=(6.626* 10^(-34) )/(4* 3.14* 1* 10^(-4)m )\\\Delta p=0.53* 10^(-30)kgms^(-1)`

Therefore, uncertainty in the transverse momentum of photon is
`0.53* 10^(-30)kgms^(-1)`