Question

An airplane flies eastward and accelerates uniformly. At one position along its path it has a velocity of 28.3 m/s. It then flies a further distance at 43.7 km and its velocity is 50.3 m/s. Find the airplanes acceleration. a) 0.02 m/s^2

b) 0.20 m/s^2
c) 2.00 m/s^2
d) 19.8 m/s^2

Answer 1

Acceleration of the airplane,
`a=0.02\ m/s^2`

Step-by-step explanation:

It is given that,

Initial velocity of the airplane, u = 28.3 m/s

Final velocity of the airplane, v = 50.3 m/s

Distance covered,
`d=43.7\ km=43.7* 10^3\ m`

We need to find the acceleration of the airplane. It is given by using third equation of motion as :

`v^2-u^2=2ad`

`a=(v^2-u^2)/(2d)`

`a=((50.3)^2-(28.3)^2)/(2* 43.7* 10^3)`

`a=0.0197\ m/s^2`

or

`a=0.02\ m/s^2`

So, the acceleration of the airplane is
`0.02\ m/s^2`. Hence, this is the required solution.