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A solid metal sphere is 15.0 cm in diameter and has surface of uniform color.When its surface is at 112°C, you measure that it radiates energy at a rate of71.3 W. What is the emissivity of the surface of this object

User Mads
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Answer:

The emissivity of the surface of this object is 0.809.

Step-by-step explanation:

Given that,

Diameter = 15.0 cm

Temperature = 112°C

Power = 71.3 W

We need to calculate the area

Using formula of area


A=4\pi r^2

Put the value into the formula


A=4\pi((15.0*10^(-2))^2)/(4)


A=0.0707\ m^2

We need to calculate the emissivity of the surface of this object

Using formula of the emissivity


P=\epsilon \sigma AT^4


\epsilon=(P)/(\sigma AT^4)

Where, A = area

T = temperature


\sigma =Stefan Boltzmann constant

P = power

Put the value into the formula


\epsilon=(71.3)/(5.670*10^(-8)*0.0707*(112+273)^4)


\epsilon=0.809

Hence, The emissivity of the surface of this object is 0.809.

User Afanasii Kurakin
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