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The Ksp for AgBr is 4.9 X 10^-13 at 25 C. What is the concentration of Ag+ in a solution in which the concentration of Br- is 0.010M?

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Answer: The concentration of
Ag^+ ion in the solution is
4.9* 10^(-11)M

Step-by-step explanation:

The balanced equilibrium reaction for the ionization of calcium fluoride follows:


AgBr\rightleftharpoons Ag^(+)+Br^-

s 0.01

The expression for solubility constant for this reaction will be:


K_(sp)=[Ag^(+)][Br^-]

We are given:


K_(sp)=4.9* 10^(-13)


[Br^-]=0.01M

Putting values in above equation, we get:


4.9* 10^(-13)=(s)* 0.01


[Ag^+]=4.9* 10^(-11)M

Hence, the concentration of
Ag^+ ion in the solution is
4.9* 10^(-11)M

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