Question

A particle of mass 6.7×10^−6 kg and charge 13 μC is moving at a speed of 70 m/s perpendicularly to a uniform 9.4-T magnetic field. What is the radius of the particle’s circular path?

Answer 1

3.8379 meters

Step-by-step explanation:

A charged particle into an uniform magnetic field describes a circular movement with radius "r" acording to the equation r=(m*v)/(q*B), where m is the mass of the particle, v its velocity, q the charge, and B the perpendicularly uniform magnetic field. Replacing your value on this equation, the radius is 3.8379 m. I suggest to verify the value of the magnetic field, because 9.4 is a extremely high magentic field.