Light from a laser strikes a diffraction grating that has 5500 lines per centimeter. The central and first-order maxima are separated by 0.455 m on a wall, 1.62 m from the grati…

Question

asked May 12, 2020 191k views

1 Answer

Shrey Joshi · Answer 1 · 2020-05-18T01:55:48+0000

.Answer:

491.4 nm

Step-by-step explanation:

The distance between central and first maxima is,

y=0.455m

And the distance between screen abnd grating is,

L=1.62 m

Now the angle can be find as,

$tan\theta=(y)/(L) \\\theta=tan^(-1)((0.455)/(1.62))  \\\theta=15.68^(\circ)$

Now the grating distance is,

$d=(1)/(5500) cm\\d=1.82* 10^(-6)m$

Now with m=1 condition will become,

$\lambda=dsin\theta$

So,

$\lambda=1.82* 10^(-6)m* sin(15.68^(\circ))\\\lambda=1.82* 10^(-6)m* 0.270\\\lambda=491.4* 10^(-9)m\\\lambda=491.4 nm$

Therefore the wavelength of laser light is 491.4 nm.

$Light from a laser strikes a diffraction grating that has 5500 lines per centimeter-example-1$