.Answer:
491.4 nm
Step-by-step explanation:
The distance between central and first maxima is,
![y=0.455m](https://img.qammunity.org/2020/formulas/physics/college/nb0hatjkztlciibmmxlp74dblj44eta6gu.png)
And the distance between screen abnd grating is,
![L=1.62 m](https://img.qammunity.org/2020/formulas/physics/college/6mzfx0ewx0pplvyw8oz9rq0fa02ioapcxf.png)
Now the angle can be find as,
![tan\theta=(y)/(L) \\\theta=tan^(-1)((0.455)/(1.62)) \\\theta=15.68^(\circ)](https://img.qammunity.org/2020/formulas/physics/college/v5uvgn9dmpx8a2m4csef5aukr8h9yjbg7j.png)
Now the grating distance is,
![d=(1)/(5500) cm\\d=1.82* 10^(-6)m](https://img.qammunity.org/2020/formulas/physics/college/xemc120e7mvgye206p4if1vfjynjamnluy.png)
Now with m=1 condition will become,
![\lambda=dsin\theta](https://img.qammunity.org/2020/formulas/physics/college/r6ieqcoptsneebwzhkdftc836v55pb9p57.png)
So,
![\lambda=1.82* 10^(-6)m* sin(15.68^(\circ))\\\lambda=1.82* 10^(-6)m* 0.270\\\lambda=491.4* 10^(-9)m\\\lambda=491.4 nm](https://img.qammunity.org/2020/formulas/physics/college/qfdu9j84b7gvlo1qvf0ubpondigxrwciix.png)
Therefore the wavelength of laser light is 491.4 nm.