Question

A flask that can withstand an internal pressure of 2500 torr, but no more, is filled with a gas at 21.0C and 758 torr and heated. At what temperature will it burst?

Answer 1

Answer : The temperature will be, 969.66 K

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

`P\propto T`

or,

`(P_1)/(T_1)=(P_2)/(T_2)`

where,

`P_1` = initial pressure of gas = 758 torr

`P_2` = final pressure of gas = 2500 torr

`T_1` = initial temperature of gas =
`21.0^oC=273+21.0=294K`

`T_2` = final temperature of gas = ?

Now put all the given values in the above equation, we get:

`(758torr)/(294K)=(2500torr)/(T_2)`

`T_2=969.66K`

Thus, the temperature will be 969.66 K