Question

Find the momentum (in kg.m/s) of a helium nucleus having a mass of 6.68 x 10^-27 kg that is moving at 0.386c.

Answer 1

`7.73544* 10^(-21)kgm/sec`

Step-by-step explanation:

We have given mass of helium nucleus
`m=6.68* 10^(-27)kg`

Velocity of helium nucleus
`v=0.386c=0.386* 3* 10^(8)m/sec=1.158* 10^(8)m/sec`

Momentum of the helium nucleus is given by
`P=mv` where m is mass and v is velocity

So
`P=mv=6.68* 10^(-27)* 1.158* 10^(8)=7.73544* 10^(-21)kgm/sec`