Question

What is the standard enthalpy of formation of CO(g). Given: AH. [C] = -393 kJ mol2. AH [CO] = -283 kJ mol2.

Answer 1

The standard enthalpy of formation of CO(g) is:

Δ
`H_r_x_n=110kJ mol2`

Step-by-step explanation:

The chemical equation to formation of CO is:

`C +(1)/(2) O_2` →
`CO`

So, we need to find the standard enthalpy of formation of CO(g) with the expression:

Δ
`H_r_x_n=`ΣΔ
`H_p_r_o_d_u_c_t_s-`ΣΔ
`H_r_e_a_g_e_n_t_s` (1)

With the information of the exercise we know:

AH [C] = -393 kJ mol2

AH [CO] = -283 kJ mol2

The enthalpy of formation of a pure compound is zero so the enthalpy of Oxygen is zero.

Now, we can replace this values in the equation (1)

Δ
`H_r_x_n=-283kJ mol2-(-393 kJ mol2)`

Δ
`H_r_x_n=110kJ mol2`