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Sulfur and oxygen form both sulfur dioxide and sulfur trioxide. When samples of these are decomposed, the sulfur dioxide produces 3.46 g oxygen and 3.47 g sulfur, while the sulfur trioxide produces 8.25 g oxygen and 5.50 g sulfur. A) Calculate the mass of oxygen per gram of sulfur for sulfur dioxide.

B) Calculate the mass of oxygen per gram of sulfur for sulfur trioxide.

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Answer:

For A: The mass of oxygen per gram of sulfur for sulfur dioxide is 0.997 g

For B: The mass of oxygen per gram of sulfur for sulfur trioxide is 1.5 g

Step-by-step explanation:

  • For A:

The chemical equation for decomposition of sulfur dioxide follows:


SO_2\rigtarrow S+O_2

We are given:

Mass of sulfur = 3.47 g

Mass of oxygen = 3.46 g

To calculate the mass of oxygen per gram of sulfur, we apply unitary method:

For every 3.47 g of sulfur, 3.46 g of oxygen will form.

So, for 1 gram of sulfur,
(3.46g)/(3.47g)* 1g=0.997g of oxygen will form.

Hence, the mass of oxygen per gram of sulfur for sulfur dioxide is 0.997 g

  • For B:

The chemical equation for decomposition of sulfur trioxide follows:


2SO_3\rigtarrow 2S+3O_2

We are given:

Mass of sulfur = 5.50 g

Mass of oxygen = 8.25 g

To calculate the mass of oxygen per gram of sulfur, we apply unitary method:

For every 5.50 g of sulfur, 8.25 g of oxygen will form.

So, for 1 gram of sulfur,
(8.25g)/(5.50g)* 1g=1.5g of oxygen will form.

Hence, the mass of oxygen per gram of sulfur for sulfur trioxide is 1.5 g

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