Question

A beam of light travels from a medium with an index of refraction of 1.27 to a medium with an index of refraction of 1.46. If the incoming beam makes an angle of 14.0° with the normal, at what angle from the normal will it refract?

Answer 1

M

Step-by-step explanation:

Answer 2

12.15°

Step-by-step explanation:

Using Snell's law as:

`n_i* {sin\theta_i}={n_r}*{sin\theta_r}`

Where,

`{\theta_i}` is the angle of incidence ( 14.0° )

`{\theta_r}` is the angle of refraction ( ? )

`{n_r}` is the refractive index of the refraction medium (n=1.46)

`{n_i}` is the refractive index of the incidence medium (n=1.27)

Hence,

`1.27* {sin14.0^0}={1.46}*{sin\theta_r}`

Angle of refraction =
`sin^(-1)0.2104` = 12.15°