Question

Copper tubes are produced by horizontal true centrifugal casting. The tube 2.4 lengths 2.0 m, outside diameter 16.0 cm, and inside diameter 15.0 cm. If the rotational speed of the pipe 900 rev/min, determine the G-factor.

Answer 1

G =67.74

Step-by-step explanation:

Given that

length l=2.4 m

Outside diameter= 16 cm

Inside diameter= 15 cm

Speed N =900 RPM

We know that

`G\ factor=(V^2)/(rg)`

Where r is the radius V is the velocity.

So mean radius

`r=(15)/(2) cm`

r = 7.5 cm

We know that

`\omega =(2\pi N)/(60)`

`\omega =(2\pi * 900)/(60)`

`\omega =94.24 rad/s`

V=ω x r

V= 94.24 x 0.075 m/s

V= 7.06 m/s

`G\ factor=(V^2)/(rg)`

`G\ factor=(7.06^2)/(0.075* 9.81)`

G =67.74