Answer:
C) 30%
Explanation:
The sum will be even if one of the primes chosen is even. There is only one even prime of the 10 primes under 30.
There are 9C2 = 36 ways to choose two odd primes from the 9 odd primes under 30, so 36 ways to choose 3 primes whose total is even. There are 10C3 = 120 ways to choose 3 primes, so the probability that 3 randomly chosen primes under 30 will have an even sum is ...
36/120 = 0.30 = 30%