Question

A car race qualifier has 10 participants. How many different ways can the top 6 cars cross the finish line?

Answer 1

There are 151,200 different ways.

Explanation:

For solving this question, we need the concept of permutation, the permutation gives as the number of ordered arrangement that can be made chosen k elements from a group of n elements. it is calculated as:

`(n!)/((n-k)!)`

So, in this case, we need to find the number of ways in which 6 top participants from the 10 participants can cross the finish line.

Now, we can replace n by 10 and k by 6 and calculate the number of permutations as:

`(10!)/((10-6)!)=151,200`

Finally, there are 151,200 different ways in which the top 6 cars can cross the finish line.