Question

The critical angle for total internal reflection for cubic zirconia surrounded by air is 27.0°. Calculate the polarizing angle for cubic zirconia.

Answer 1

Polarizing angle,
`\theta_(P) = tan^(- 1){2.2} = 65.56^(\circ)`

Given:

Critical angle,
`\theta_(cr) = 27^(\circ)`

Solution:

Now, in Total Internal Reflection (TIR), the critical angle for cubic zirconia is given by:

`sin\theta_(cr) = (1)/(\mu_(Z))` (1)

where

`{\mu_(Z)` = refractive index of zirconia

From eqn (1):

`\mu_(Z) = (1)/(sin\theta_(cr))`

`\mu_(Z) = (1)/(sin(27^(\circ))) = 2.2`

Now, the angle of polarization is given by:

tan
`\theta_(P) = \mu_(Z)`

Therefore,

`\theta_(P) = tan^(- 1){2.2} = 65.56^(\circ)`