Question

What is the force on a charge 5 mC, when it enters an electric field of strength 660 N/C. Give your answer in newtons.

Answer 1

`F=3300 *10^(-3)  N`

Step-by-step explanation:

The electric field is defined as the electric force (F) per unit of charge (q) . The formula to calculate electric field (E) is:

`E=(F)/(q)` Formula (1)

Where:

E: Electric field in
`(N)/(C)`

F: Force in Newtons(N)

q = Electric charge in Coulombs(C)

We know the following data:

`E=660 (N)/(C)`

q =5 mC ,
`1 mC=1*10^(-3) C` ,then,
`q=5 *10^(-3) C`

Development of the problem:

In formula (1 ) We replace the known data :

`E=(F)/(q)`

`660 (N)/(C) =(F)/(5 *10^(-3)C)`

`F =660 (N)/(C)* 5 *10^(-3) C`

`F=3300 *10^(-3)  N`