Question

A 9.12 microFarad capacitor is measured to have a reactance of 268.0 Ohm. At what frequency (in Hz) is it being driven?

Answer 1

65.14 Hz

Step-by-step explanation:

We have given the capacitance
`C=9.12\mu F=9.12* 106{-6}F`

And the capacitive reluctance = 268 ohm

The capacitive reluctance of a capacitive circuit is given by

`X_C=(1)/(\omega C)`

`X_C=(1)/(2\pi f C)`

`268=(1)/(2\pi f * 9.12* 10^(-6))`

`f=(1)/(2* 3.14* 268* 9.12* 10^(-6))=65.14Hz`