A 9.12 microFarad capacitor is measured to have a reactance of 268.0 Ohm. At what frequency (in Hz) is it being driven?

Question

asked Aug 5, 2020 34.5k views

1 Answer

Grokpot · Answer 1 · 2020-08-09T14:39:33+0000

Answer:

65.14 Hz

Step-by-step explanation:

We have given the capacitance
$C=9.12\mu F=9.12* 106{-6}F$

And the capacitive reluctance = 268 ohm

The capacitive reluctance of a capacitive circuit is given by

$X_C=(1)/(\omega C)$

$X_C=(1)/(2\pi f C)$

$268=(1)/(2\pi f * 9.12* 10^(-6))$

f=(1)/(2* 3.14* 268* 9.12* 10^(-6))=65.14Hz