Question

What is the limiting reactant and theoretical yield if 0.483 mol of Ti and 0.911 mol Clare used in this reaction: Ti + 2Cl2 → Ticle 10)

Answer 1

Answer : The limiting reactant is
`Cl_2` and the theoretical yield will be 86.45 grams.

Explanation : Given,

Moles of
`Ti` = 0.483 mole

Moles of
`Cl_2` = 0.911 mole

Molar mass of
`TiCl_4` = 190 g/mole

First we have to calculate the limiting and excess reagent.

The given balanced chemical reaction is,

`Ti+2Cl_2\rightarrow TiCl_4`

From the balanced reaction we conclude that

As, 2 moles of
`Cl_2` react with 1 mole of
`Ti`

So, 0.911 moles of
`Cl_2` react with
`(0.911)/(2)=0.455` moles of
`Ti`

From this we conclude that,
`Ti` is an excess reagent because the given moles are greater than the required moles and
`Cl_2` is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of
`TiCl_4`.

As, 2 moles of
`Cl_2` react to give 1 moles of
`TiCl_4`

So, 0.911 moles of
`Cl_2` react to give
`(0.911)/(2)=0.455` moles of
`TiCl_4`

Now we have to calculate the mass of
`TiCl_4`.

`\text{Mass of }TiCl_4=\text{Moles of }TiCl_4* \text{Molar mass of }TiCl_4`

`\text{Mass of }TiCl_4=(0.455mole)* (190g/mole)=86.45g`

Therefore, the theoretical yield will be 86.45 grams.