Question

Two clowns are launched from the same spring-loaded circus cannon with the spring compressed the same distance each time. Clown A has a 40-kg mass; clown B a 60-kg mass. The relation between their kinetic energies at the instant of launch is

Answer 1

The relation between the kinetic energies of two clowns launched from the same spring-loaded circus cannon depends on their masses and velocities.

Step-by-step explanation:

The relation between the kinetic energies of two clowns launched from the same spring-loaded circus cannon depends on their masses. The kinetic energy of an object is given by the equation KE = 1/2 * m * vЕ², where m is the mass of the object and v is its velocity.

Given that clown A has a mass of 40 kg and clown B has a mass of 60 kg, we can compare their kinetic energies using the equation:

KE(A) / KE(B) = (1/2 * 40 * v_A²) / (1/2 * 60 * v_B²)

Simplifying this equation, we get:

KE(A) / KE(B) = (40 * v_A²) / (60 * v_B²)

Therefore, the relation between their kinetic energies at the instant of launch depends on the velocities of the clowns, as well as their masses.