Question

The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = y minus 1 equals StartFraction one-fourth EndFraction left-parenthesis x minus 12 right-parenthesis.(x – 12). What is the standard form of the equation for this line? x – 4y = 8 x – 4y = 2 4x – y = 8 4x – y = 2

Answer 1

A

Explanation:

To simplify the first persons answer

Answer 2

The equation of the line in standard form is

`x-4y=8`

Explanation:

The equation of the line in point slope form is

`y-y1=m(x-x1)`

we have

`y-1=(1/4)(x-12)`

so

`m=1/4`

`(12, 1)`

step 2

Find the equation of the line in standard form

The equation of the line in standard form is

`Ax+By=C`

where

A is positive integer

B and C are integers

we have

`y-1=(1/4)(x-12)`

Multiply by 4 both sides to remove the fraction

`4y-4=(x-12)`

`x-4y=12-4\\x-4y=8`