Question

The production of ammonia (NH3) under standard conditions at 25°C is represented by the following thermochemical equation. N2(g) + 3 H2(g) → 2 NH3(g); ΔH = −91.8 kJ How much heat is released when 1.663 ✕ 104 grams of ammonia is produced?

Answer 1

44,901 kilo Joule heat is released when
`1.663* 10^4 g` grams of ammonia is produced.

Step-by-step explanation:

Moles of ammonia gas produced :

`(1.663* 10^4 g)/(17 g/mol)=978.235 mol`

According to reaction, when 2 moles of ammonia are produced 9.18 kilo joules of energy is also released.

So, When 978.235 moles of ammonia gas is produced the energy released will be:

`(-91.8 kJ)/(2)* 978.235 mol=-44,900.98 kJ\approx -44,901 kJ`

(negative sign indicates that energy is released as heat)

44,901 kilo Joule heat is released when
`1.663* 10^4 g` grams of ammonia is produced.