Question

Find the velocity (in m/s) of a proton that has a momentum of 4.96 X 10^-19 kg.m/s.

Answer 1

The velocity of the proton is
`2.965*10^(8) (m)/(s)`

Step-by-step explanation:

The momentum of a particle is defined as the product of its mass by its velocity and we can calculate it using the following formula:

p=m*v Equation (1)

Where:

p: Is the momentum in kg*m/s

m: Is mass of the particle in kg

v: Is the velocity of the particle in m/s

Data known:

m= 1,6726 × 10^–27 kg : mass of the proton

p= 4.96 X 10^-19 kg.m/s.

We replace this data in the Equation (1):

`4,96*10^(-19) =1.6726*10^(-27) *v`
`</p><p>v=(4.9*10^(-19) )/(1.6726*10^(-27) )`

`v=((4.96)/(1.6726) )*(10^(27-19) )`

`v=2,965*10^(8) m/s`

Answer: The velocity of the proton is
`2.965*10^(8) (m)/(s)`