Question

What is the volume of a tank of nitrogen if it contains 17 moles of nitrogen at 34 C under 12,000 Pa?

Answer 1

The volume of the tank of nitrogen, given that the tank contains 17 moles of nitrogen at 34 °C under 12000 Pa, is 3631.19 Liters

How to calculate the volume of the nitrogen tank?

From the question given above, the nitrogen tank contains the follow:

Number of mole of nitrogen present in tank (n) = 17 moles

• Temperature (T) = 34 °C = 34 + 273 = 307 K
• Pressure (P) = 12000 Pa = 12000 / 101325 = 0.118 atm
• Gas constant (R) = 0.0821 atm.L/molK
• Volume of nitrogen tank (V) =?

The volume of the tank of nitrogen can be calculated using the ideal gas equation as follow:

PV = nRT

0.118 × V = 17 × 0.0821 × 307

0.118 × V = 428.4799

Divide both sides by 0.118

V = 428.4799 / 0.118

= 3631.19 Liters

Thus, the nitrogen tank has a volume of 3631.19 Liters

Answer 2

Answer: 3571 L

Step-by-step explanation:

According to the ideal gas equation:'

`PV=nRT`

P = Pressure of the gas = 12000 Pa = 0.12 atm
`1Pa=9.9* 10^(-6)atm`

V= Volume of the gas = volume of tank = ?

T= Temperature of the gas = 34°C = 307 K
`0^0C=273K`

R= Gas constant = 0.0821 atmL/K mol

n= moles of gas= 17

`V=(nRT)/(P)=(17* 0.0821* 307)/(0.12)=3571 L`

Therefore Volume of tank is 3571 Liters.