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Light shined through a single slit will produce a diffraction pattern. Green light (565 nm) is shined on a slit with width 0.210 mm. (a) Find the width of the central maximum located 1.80 m from the slit. (b) Determine the width of the first order bright fringe.

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Answer:(a)9.685 mm

(b)4.184 mm

Step-by-step explanation:

Given

Wavelength of light
(\lambda )=565nm \approx 565* 10^(-9)m

Width of slit(b)=0.210

(a)Width of central maximum located 1.80m from slit


=(2\lambda L)/(b)


=(2* 565* 10^(-9)* 1.8)/(0.210* 10^(-3))

=9.685 mm

(b)Width of the first order bright fringe


Y_1=(\lambda * L)/(b)


Y_1=(565* 10^(-9)* 1.8)/(0.210* 10^(-3))


Y_1=4.84mm

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