Answer:
(a) Let be a subset of a vector space . is a subspace of if and only if the following two conditions hold:
i) is closed under the sum operation. That is to say, whenever are elements of .
ii) is closed under the scalar multiplication. That is to say, whenever and
Explanation:
For the part (b) we have the set of all sequences of the form, where . Observe the if you multiply any sequence of this form by and scalar then the sequence stops being like the given form. For example, let . Then:
This implies that the set under consideration is not closet under scalar multiplication, which implies that the set is not a subspace of the vector space of all sequences.
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