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35 votes
35 votes
A 150 g egg is dropped from 3.0 meters. The egg is moving at 4.4 m/s right before it hits the ground. The egg comes to a stop in 0.072 seconds.

What is the magnitude of force that the ground exerted on the egg?

0.66 N
9.2 N
13 N
180 N

User MTurPash
by
2.5k points

1 Answer

8 votes
8 votes

Answer:

(b) 9.2 N

Explanation:

The acceleration is the change in velocity divided by the change in time:

a = (-4.4 m/s)/(0.072 s) = -61 1/9 m/s²

The force is given by ...

F = ma = (0.150 kg)(-61 1/9 m/s²) = -9 1/6 N ≈ -9.2 N

The ground exerts a force of about 9.2 N upward on the egg.

User Ksenia
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2.5k points