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What is the work required to deflect a linear spring (k=32 kN/m) by 120 cm?

User Creack
by
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1 Answer

2 votes

Answer:

the work done by the linear spring will be equal to 23.04 k J

Step-by-step explanation:

given,

k = 32 k N /m

deflected spring = 120 cm

= 1.2 m

work done by spring can be calculate as

=
(1)/(2)kx^2

=
(1)/(2)* 32 * 1.2^2

= 23.04 k J

hence, the work done by the linear spring will be equal to 23.04 k J

User ColonD
by
8.4k points