Question

Arrange the following compounds in decreasing order of acidity from left to right, and explain the reason in less than 90 words. CH3COOH CC13COOH CF3COOH CBr3COOH

Answer 1

The compounds can be arranged in decreasing order of acidity as follows: CF3COOH, CBr3COOH, CCl3COOH, CH3COOH. The acidity of a compound is determined by the stability of the resulting conjugate base after losing a proton.

Step-by-step explanation:

The compounds can be arranged in decreasing order of acidity as follows:

1. CF3COOH
2. CBr3COOH
3. CCl3COOH
4. CH3COOH

The acidity of a compound is determined by the stability of the resulting conjugate base after losing a proton. In this case, the order of decreasing acidity is determined by the presence and number of electronegative atoms.

Answer 2

Step-by-step explanation:

More is the electronegativity of atoms attached to the alpha carbon atom more will be the attraction of electron towards it. As a result, release of hydrogen ion will be easier.

Therefore, there will be increased in acidity of the compound.

Since, fluorine, chlorine and bromine are all group 17 elements and fluorine is more reactive than chlorine. On the other hand, chlorine is more reactive than bromine.

Hence, ability to attract the electrons towards itself will be maximum in fluorine and least in bromine.

Therefore, decreasing order of acidity of the given compounds is as follows.

`CF_(3)COOH` >
`CCl_(3)COOH` >
`CBr_(3)COOH` >
`CH_(3)COOH`