Question

A medical team sent surveys to randomly selected households to determine the various health problems. The result of the survey is shown below.

health problems, number of patients

obesity 32

diabetes 54

heart problems 78

eye problems 112

dental problems 96


Note: The survey result for each health problem is mutually exclusive.


Based on the survey, what is the probability that a person chosen at random is a diabetic patient or an eye patient?

(SHOW WORK)

Answer 1

Step-by-step explanation: First of all, we asume that each household recive a survey to check all health problems. After that we can sume all patients that means 32+54+78+112+96=372.

Now with a simple rule of three:

=30.11%. We have the 30.11% of the patients have eye problems.

=14.52%. We have the 14.52% of the patients have diabetes problems.

Answer 2

Answer: Our required probability would be
`(83)/(186)`

Explanation:

Since we have given that

Health problems Number of patients

Obesity 32

Diabetes 54

Heart problems 78

Eye problems 112

Dental problems 96

Total 372

We need to find the probability that a person chosen at random is a diabetic patient or an eye patient.

So, P(diabetic patient) + P(eye patient)

`(54)/(372)+(112)/(372)\\\\=(54+112)/(372)\\\\=(166)/(372)\\\\=(83)/(186)`

Hence, our required probability would be
`(83)/(186)`