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Answer:
8πr + 4π
Explanation:
Your mistake in solving this problem was using the formula for volume rather than find the difference in area.
a(r) = 4πr^2
a = a(r + 1) - a(r)
a = [4π(r + 1)^2]
a = 4π(r^2 - r^2 + 2r + 1)
a = 4π(2r + 1)
a = 8πr + 4π
Best of Luck!
you have used the volume formula when the problem asks for a difference of area.
ΔA = 4π(2r+1) = 8πr +4π
A(r) = 4πr²
ΔA = A(r+1) - A(r) = (4π(r+1)²) -4πr² = 4π(r² +2r +1 - r²)
ΔA = 4π(2r +1) = 8πr +4π
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