Question

the length of the picture fram is 3in. greater than the width. The perimeter is less than 52in. Describe the dimensions of the frame

Answer 1

length = 14.5 in

Width = 11.50 in

Explanation:

Let the length of the picture = x

width be = y

Perimeter P=52

P is given as

P=2(x+y)

56=2(x+y)

x+y=28 (Dividing both sides by 2) ---(A)

Also given that

the length of the picture fram is 3 in greater than the width.

x-y=3 ----(B)

Adding A and B

2x=29

dividing both sides by 2 we get

x=14.5

Putting this in B we get

14.5-y=3y=11.5