Question

Find three consecutive even integers, such that

5 times of first integer is 18 more than the sum
of second and third integers.

Answer 1

8,10 ,12

Explanation:

x

x+2

x+4

5x-18 =x+2 + x+4

5x-18=2x+6

3x=24

x=8

8*5=40 40-18= 22

10+12 = 22