Question

Please help I’m confused on how to find the quotient on this problem

Answer 1

3x^2 +3hx +h^2 +3

Explanation:

As with any function evaluation, substitute the argument for x and simplify.

Quotient

Using the definition of f(x), and using the given arguments, we have ...

`(f(x+h)-f(x))/(h)=(((x+h)^3+3(x+h))\ -\ (x^3+3x))/(h)\\\\=(((x^3+3hx^2+3h^2x+h^3)+(3x+3h))-x^3-3x)/(h)\\\\=((1-1)x^3+3hx^2+(3h^2+3-3)x+(h^3+3h))/(h)=(3hx^2+3h^2x+h(h^2+3))/(h)\\\\=\boxed{3x^2+3hx +h^2+3}`