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Consider the set A = {a, (b), c). What is the power set of A? O{0, {a}, {a,{b}}, {{b}}, {c,a}, {{b},c}, {C}, {a,{b},c}} O{0, {a}, {b}, {C}, {a,b}, {a,c}, {b,c}, {a,b,c}} O{0, {a}, {a,{b}}, {{b}}, {a,b,c}, {{b},c}, {C}, {a,{b},c}} O{0, a, b, c, {a,b}, {a,c}, {b,c}, {a,b,c}}

User Jens Wirth
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2 Answers

4 votes

Answer:

the answer will be 0

Explanation:

User BJ Miller
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8.9k points
6 votes

Answer:

O{{}, {a}, {{b}}, {c}, {a,{b}}, {a,c}, {{b},c}, {a,{b},c}}.

Explanation:

You have the following set:

A = {a, {b},c}

The power set of any set A is the set that contains all the subsets of A.

Each set B is a subset of A if B is contained in A.

Each N-cardinality set will have a
2^(N)-1-cardinality power set.

The subsets of A are:

- The empty set(The empty set is a subset of any set)

- Each element of A. So {a}, {{b}}, {c} are all subsets of A.

- Every combination between elements of A are subsets of A. So {a,{b}}, {a,c}, {{b},c} and {a,{b},c} are all subsets of A.

So the power set of A is

O{{}, {a}, {{b}}, {c}, {a,{b}}, {a,c}, {{b},c}, {a,{b},c}}.

User Niedved
by
7.6k points

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