First, convert the 112 and 130 to z-scores:
z1 = (112 - 103) / 9 = 1
z2 = (130 - 103) / 9 = 3
Now find the area under the normal curve between z = 1 and z = 3. You can do this by looking in a z-table. I will do it using my TI-83:
normalcdf(1,3) = .1573052923 <----answer